# Will Nathan Drake Jump Into the Unknown Trailer?

The time it takes Drake to move straight is the same time it takes for him to move horizontally. This means that I can use the horizontal movement to calculate the time, and then use the time by moving vertically to find its fixed position.

When Drake jumped, he had to climb to a height of zero meters; That’s where the ramp is and that’s where I put the origin. If the final cost is less than zero meters, they land below flight. And that would be bad.

Identifying a horizontal motion is not very difficult. Since it has a steady speed, I can find its horizontal position with the following equation:

Note this: I know the starting point x-location (x1 = 2.4 m) and x-end position (x2 = 0 m) to be able to use x-speed to eliminate the time required to complete the jump. (Moving to the left, then it will be 3.37 m / s.)

Note that in this trailer we do not see any jumps, but, if we do, it would take 0.71 seconds to reach the rear of the plane.

Now, I can use this time and connect it into a standalone kinematic equation. This gives the last place ay bad 1.79 m.

This is lower than zero, so there is nothing but air under it. And remember: that is bad.

We have not finished yet, but it is better to take a second surprise because he ends up though down than he started. This is because even though its initial speed is in good (climbing) mode, the jump takes so long that the force of gravity stops its movement upwards and causes it to descend faster and faster.